3.17.1 \(\int \frac {1}{(1-2 x)^2 (2+3 x)^5 (3+5 x)} \, dx\) [1601]

3.17.1.1 Optimal result
3.17.1.2 Mathematica [A] (verified)
3.17.1.3 Rubi [A] (verified)
3.17.1.4 Maple [A] (verified)
3.17.1.5 Fricas [B] (verification not implemented)
3.17.1.6 Sympy [A] (verification not implemented)
3.17.1.7 Maxima [A] (verification not implemented)
3.17.1.8 Giac [A] (verification not implemented)
3.17.1.9 Mupad [B] (verification not implemented)

3.17.1.1 Optimal result

Integrand size = 22, antiderivative size = 86 \[ \int \frac {1}{(1-2 x)^2 (2+3 x)^5 (3+5 x)} \, dx=\frac {32}{184877 (1-2 x)}+\frac {9}{196 (2+3 x)^4}+\frac {117}{343 (2+3 x)^3}+\frac {12393}{4802 (2+3 x)^2}+\frac {434043}{16807 (2+3 x)}-\frac {6400 \log (1-2 x)}{14235529}-\frac {15192225 \log (2+3 x)}{117649}+\frac {15625}{121} \log (3+5 x) \]

output
32/184877/(1-2*x)+9/196/(2+3*x)^4+117/343/(2+3*x)^3+12393/4802/(2+3*x)^2+4 
34043/16807/(2+3*x)-6400/14235529*ln(1-2*x)-15192225/117649*ln(2+3*x)+1562 
5/121*ln(3+5*x)
 
3.17.1.2 Mathematica [A] (verified)

Time = 0.09 (sec) , antiderivative size = 81, normalized size of antiderivative = 0.94 \[ \int \frac {1}{(1-2 x)^2 (2+3 x)^5 (3+5 x)} \, dx=\frac {5 \left (\frac {77}{5} \left (\frac {128}{1-2 x}+\frac {33957}{(2+3 x)^4}+\frac {252252}{(2+3 x)^3}+\frac {1908522}{(2+3 x)^2}+\frac {19097892}{2+3 x}\right )-5120 \log (5-10 x)-1470607380 \log (5 (2+3 x))+1470612500 \log (3+5 x)\right )}{56942116} \]

input
Integrate[1/((1 - 2*x)^2*(2 + 3*x)^5*(3 + 5*x)),x]
 
output
(5*((77*(128/(1 - 2*x) + 33957/(2 + 3*x)^4 + 252252/(2 + 3*x)^3 + 1908522/ 
(2 + 3*x)^2 + 19097892/(2 + 3*x)))/5 - 5120*Log[5 - 10*x] - 1470607380*Log 
[5*(2 + 3*x)] + 1470612500*Log[3 + 5*x]))/56942116
 
3.17.1.3 Rubi [A] (verified)

Time = 0.22 (sec) , antiderivative size = 86, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {99, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {1}{(1-2 x)^2 (3 x+2)^5 (5 x+3)} \, dx\)

\(\Big \downarrow \) 99

\(\displaystyle \int \left (-\frac {45576675}{117649 (3 x+2)}+\frac {78125}{121 (5 x+3)}-\frac {1302129}{16807 (3 x+2)^2}-\frac {37179}{2401 (3 x+2)^3}-\frac {1053}{343 (3 x+2)^4}-\frac {27}{49 (3 x+2)^5}-\frac {12800}{14235529 (2 x-1)}+\frac {64}{184877 (2 x-1)^2}\right )dx\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {32}{184877 (1-2 x)}+\frac {434043}{16807 (3 x+2)}+\frac {12393}{4802 (3 x+2)^2}+\frac {117}{343 (3 x+2)^3}+\frac {9}{196 (3 x+2)^4}-\frac {6400 \log (1-2 x)}{14235529}-\frac {15192225 \log (3 x+2)}{117649}+\frac {15625}{121} \log (5 x+3)\)

input
Int[1/((1 - 2*x)^2*(2 + 3*x)^5*(3 + 5*x)),x]
 
output
32/(184877*(1 - 2*x)) + 9/(196*(2 + 3*x)^4) + 117/(343*(2 + 3*x)^3) + 1239 
3/(4802*(2 + 3*x)^2) + 434043/(16807*(2 + 3*x)) - (6400*Log[1 - 2*x])/1423 
5529 - (15192225*Log[2 + 3*x])/117649 + (15625*Log[3 + 5*x])/121
 

3.17.1.3.1 Defintions of rubi rules used

rule 99
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) 
)^(p_), x_] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*x)^n*(e + f*x)^p, x], 
 x] /; FreeQ[{a, b, c, d, e, f, p}, x] && IntegersQ[m, n] && (IntegerQ[p] | 
| (GtQ[m, 0] && GeQ[n, -1]))
 

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 
3.17.1.4 Maple [A] (verified)

Time = 2.70 (sec) , antiderivative size = 61, normalized size of antiderivative = 0.71

method result size
norman \(\frac {-\frac {194642025}{369754} x +\frac {186937875}{369754} x^{2}+\frac {257818950}{184877} x^{4}+\frac {395313750}{184877} x^{3}-\frac {160957733}{739508}}{\left (-1+2 x \right ) \left (2+3 x \right )^{4}}-\frac {6400 \ln \left (-1+2 x \right )}{14235529}-\frac {15192225 \ln \left (2+3 x \right )}{117649}+\frac {15625 \ln \left (3+5 x \right )}{121}\) \(61\)
risch \(\frac {-\frac {194642025}{369754} x +\frac {186937875}{369754} x^{2}+\frac {257818950}{184877} x^{4}+\frac {395313750}{184877} x^{3}-\frac {160957733}{739508}}{\left (-1+2 x \right ) \left (2+3 x \right )^{4}}-\frac {6400 \ln \left (-1+2 x \right )}{14235529}-\frac {15192225 \ln \left (2+3 x \right )}{117649}+\frac {15625 \ln \left (3+5 x \right )}{121}\) \(62\)
default \(\frac {15625 \ln \left (3+5 x \right )}{121}-\frac {32}{184877 \left (-1+2 x \right )}-\frac {6400 \ln \left (-1+2 x \right )}{14235529}+\frac {9}{196 \left (2+3 x \right )^{4}}+\frac {117}{343 \left (2+3 x \right )^{3}}+\frac {12393}{4802 \left (2+3 x \right )^{2}}+\frac {434043}{16807 \left (2+3 x \right )}-\frac {15192225 \ln \left (2+3 x \right )}{117649}\) \(71\)
parallelrisch \(-\frac {-313601758624 x +2823576000000 \ln \left (x +\frac {3}{5}\right ) x^{2}+25412095526400 \ln \left (\frac {2}{3}+x \right ) x^{3}+7529536000000 \ln \left (x +\frac {3}{5}\right ) x -2823566169600 \ln \left (\frac {2}{3}+x \right ) x^{2}-7529509785600 \ln \left (\frac {2}{3}+x \right ) x +2007786761442 x^{5}+728942855256 x^{3}+3079672864191 x^{4}-758064814584 x^{2}+143769600 \ln \left (x -\frac {1}{2}\right ) x^{4}+41294655230400 \ln \left (\frac {2}{3}+x \right ) x^{4}-1882377446400 \ln \left (\frac {2}{3}+x \right )+88473600 \ln \left (x -\frac {1}{2}\right ) x^{3}-9830400 \ln \left (x -\frac {1}{2}\right ) x^{2}-26214400 \ln \left (x -\frac {1}{2}\right ) x +1882384000000 \ln \left (x +\frac {3}{5}\right )+19059071644800 \ln \left (\frac {2}{3}+x \right ) x^{5}-25412184000000 \ln \left (x +\frac {3}{5}\right ) x^{3}-19059138000000 \ln \left (x +\frac {3}{5}\right ) x^{5}-41294799000000 \ln \left (x +\frac {3}{5}\right ) x^{4}-6553600 \ln \left (x -\frac {1}{2}\right )+66355200 \ln \left (x -\frac {1}{2}\right ) x^{5}}{911073856 \left (-1+2 x \right ) \left (2+3 x \right )^{4}}\) \(188\)

input
int(1/(1-2*x)^2/(2+3*x)^5/(3+5*x),x,method=_RETURNVERBOSE)
 
output
(-194642025/369754*x+186937875/369754*x^2+257818950/184877*x^4+395313750/1 
84877*x^3-160957733/739508)/(-1+2*x)/(2+3*x)^4-6400/14235529*ln(-1+2*x)-15 
192225/117649*ln(2+3*x)+15625/121*ln(3+5*x)
 
3.17.1.5 Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 148 vs. \(2 (70) = 140\).

Time = 0.23 (sec) , antiderivative size = 148, normalized size of antiderivative = 1.72 \[ \int \frac {1}{(1-2 x)^2 (2+3 x)^5 (3+5 x)} \, dx=\frac {79408236600 \, x^{4} + 121756635000 \, x^{3} + 28788432750 \, x^{2} + 7353062500 \, {\left (162 \, x^{5} + 351 \, x^{4} + 216 \, x^{3} - 24 \, x^{2} - 64 \, x - 16\right )} \log \left (5 \, x + 3\right ) - 7353036900 \, {\left (162 \, x^{5} + 351 \, x^{4} + 216 \, x^{3} - 24 \, x^{2} - 64 \, x - 16\right )} \log \left (3 \, x + 2\right ) - 25600 \, {\left (162 \, x^{5} + 351 \, x^{4} + 216 \, x^{3} - 24 \, x^{2} - 64 \, x - 16\right )} \log \left (2 \, x - 1\right ) - 29974871850 \, x - 12393745441}{56942116 \, {\left (162 \, x^{5} + 351 \, x^{4} + 216 \, x^{3} - 24 \, x^{2} - 64 \, x - 16\right )}} \]

input
integrate(1/(1-2*x)^2/(2+3*x)^5/(3+5*x),x, algorithm="fricas")
 
output
1/56942116*(79408236600*x^4 + 121756635000*x^3 + 28788432750*x^2 + 7353062 
500*(162*x^5 + 351*x^4 + 216*x^3 - 24*x^2 - 64*x - 16)*log(5*x + 3) - 7353 
036900*(162*x^5 + 351*x^4 + 216*x^3 - 24*x^2 - 64*x - 16)*log(3*x + 2) - 2 
5600*(162*x^5 + 351*x^4 + 216*x^3 - 24*x^2 - 64*x - 16)*log(2*x - 1) - 299 
74871850*x - 12393745441)/(162*x^5 + 351*x^4 + 216*x^3 - 24*x^2 - 64*x - 1 
6)
 
3.17.1.6 Sympy [A] (verification not implemented)

Time = 0.11 (sec) , antiderivative size = 75, normalized size of antiderivative = 0.87 \[ \int \frac {1}{(1-2 x)^2 (2+3 x)^5 (3+5 x)} \, dx=\frac {1031275800 x^{4} + 1581255000 x^{3} + 373875750 x^{2} - 389284050 x - 160957733}{119800296 x^{5} + 259567308 x^{4} + 159733728 x^{3} - 17748192 x^{2} - 47328512 x - 11832128} - \frac {6400 \log {\left (x - \frac {1}{2} \right )}}{14235529} + \frac {15625 \log {\left (x + \frac {3}{5} \right )}}{121} - \frac {15192225 \log {\left (x + \frac {2}{3} \right )}}{117649} \]

input
integrate(1/(1-2*x)**2/(2+3*x)**5/(3+5*x),x)
 
output
(1031275800*x**4 + 1581255000*x**3 + 373875750*x**2 - 389284050*x - 160957 
733)/(119800296*x**5 + 259567308*x**4 + 159733728*x**3 - 17748192*x**2 - 4 
7328512*x - 11832128) - 6400*log(x - 1/2)/14235529 + 15625*log(x + 3/5)/12 
1 - 15192225*log(x + 2/3)/117649
 
3.17.1.7 Maxima [A] (verification not implemented)

Time = 0.21 (sec) , antiderivative size = 74, normalized size of antiderivative = 0.86 \[ \int \frac {1}{(1-2 x)^2 (2+3 x)^5 (3+5 x)} \, dx=\frac {1031275800 \, x^{4} + 1581255000 \, x^{3} + 373875750 \, x^{2} - 389284050 \, x - 160957733}{739508 \, {\left (162 \, x^{5} + 351 \, x^{4} + 216 \, x^{3} - 24 \, x^{2} - 64 \, x - 16\right )}} + \frac {15625}{121} \, \log \left (5 \, x + 3\right ) - \frac {15192225}{117649} \, \log \left (3 \, x + 2\right ) - \frac {6400}{14235529} \, \log \left (2 \, x - 1\right ) \]

input
integrate(1/(1-2*x)^2/(2+3*x)^5/(3+5*x),x, algorithm="maxima")
 
output
1/739508*(1031275800*x^4 + 1581255000*x^3 + 373875750*x^2 - 389284050*x - 
160957733)/(162*x^5 + 351*x^4 + 216*x^3 - 24*x^2 - 64*x - 16) + 15625/121* 
log(5*x + 3) - 15192225/117649*log(3*x + 2) - 6400/14235529*log(2*x - 1)
 
3.17.1.8 Giac [A] (verification not implemented)

Time = 0.28 (sec) , antiderivative size = 82, normalized size of antiderivative = 0.95 \[ \int \frac {1}{(1-2 x)^2 (2+3 x)^5 (3+5 x)} \, dx=\frac {434043}{16807 \, {\left (3 \, x + 2\right )}} + \frac {192}{1294139 \, {\left (\frac {7}{3 \, x + 2} - 2\right )}} + \frac {12393}{4802 \, {\left (3 \, x + 2\right )}^{2}} + \frac {117}{343 \, {\left (3 \, x + 2\right )}^{3}} + \frac {9}{196 \, {\left (3 \, x + 2\right )}^{4}} + \frac {15625}{121} \, \log \left ({\left | -\frac {1}{3 \, x + 2} + 5 \right |}\right ) - \frac {6400}{14235529} \, \log \left ({\left | -\frac {7}{3 \, x + 2} + 2 \right |}\right ) \]

input
integrate(1/(1-2*x)^2/(2+3*x)^5/(3+5*x),x, algorithm="giac")
 
output
434043/16807/(3*x + 2) + 192/1294139/(7/(3*x + 2) - 2) + 12393/4802/(3*x + 
 2)^2 + 117/343/(3*x + 2)^3 + 9/196/(3*x + 2)^4 + 15625/121*log(abs(-1/(3* 
x + 2) + 5)) - 6400/14235529*log(abs(-7/(3*x + 2) + 2))
 
3.17.1.9 Mupad [B] (verification not implemented)

Time = 1.35 (sec) , antiderivative size = 68, normalized size of antiderivative = 0.79 \[ \int \frac {1}{(1-2 x)^2 (2+3 x)^5 (3+5 x)} \, dx=\frac {15625\,\ln \left (x+\frac {3}{5}\right )}{121}-\frac {15192225\,\ln \left (x+\frac {2}{3}\right )}{117649}-\frac {6400\,\ln \left (x-\frac {1}{2}\right )}{14235529}-\frac {\frac {1591475\,x^4}{184877}+\frac {7320625\,x^3}{554631}+\frac {2307875\,x^2}{739508}-\frac {64880675\,x}{19966716}-\frac {160957733}{119800296}}{-x^5-\frac {13\,x^4}{6}-\frac {4\,x^3}{3}+\frac {4\,x^2}{27}+\frac {32\,x}{81}+\frac {8}{81}} \]

input
int(1/((2*x - 1)^2*(3*x + 2)^5*(5*x + 3)),x)
 
output
(15625*log(x + 3/5))/121 - (15192225*log(x + 2/3))/117649 - (6400*log(x - 
1/2))/14235529 - ((2307875*x^2)/739508 - (64880675*x)/19966716 + (7320625* 
x^3)/554631 + (1591475*x^4)/184877 - 160957733/119800296)/((32*x)/81 + (4* 
x^2)/27 - (4*x^3)/3 - (13*x^4)/6 - x^5 + 8/81)